[LeetCode with Python] 58. Length of Last Word

Difficulty : Easy

 

Approach 1 : use rstrip to treat with case with rightside spaces.

 

class Solution:
    def lengthOfLastWord(self, s: str) -> int:
        count = 0
        s = s.rstrip()
        for i in range(len(s) - 1, -1, -1):
            if s[i] == " ":
                break
            count += 1

        return count

 

Approach 2 : no rstrip, put another if when the letter we encountered is space to check it's rightside space or not. too slow :(

class Solution:
    def lengthOfLastWord(self, s: str) -> int:
        count = 0
        have_to_break = False
        for i in range(len(s) - 1, -1, -1):
            if s[i] == " ":
                if have_to_break:
                    break
            else:
                have_to_break = True
                count += 1

        return count